2x + 2y = 0
y = 4x + 0
2006-08-27 01:03:15 · 11 answers · asked by wvgirl 1 in Science & Mathematics ➔ Mathematics
Indeed dear i would help you and teach you all i can
so lets get started
First function is 2x + 2y = 0
Second function is y = 4x + 0 ; y - 4x =0
so now we have 2 functions
step 1;
2x + 2y = 0
y - 4x = 0
step 2;
now we need to remove " x " or " y ",so i chose" x "
(+2) * [ 2x + 2y = 0] + (y - 4x = 0)
step 3;
(4x +4y = 0) + ( y - 4x = 0 )
(4x-4x) + ( 4y +y ) = (0+0)
5y =0
y = 5/0 = 0
so y = 0
step 4;
we just need to put " y " in one of functions and get " x ".It's up to you,i chose the first function ,i mean 2x + 2y = 0
if y= 0
so
2x +( 2*0 ) = 0
2x + 0 = 0
2x = 0
x= 0/2
x = 0
x= 0 & y= 0
Good Luck Darling.
2006-08-27 02:06:06 · answer #1 · answered by sweetie 5 · 2⤊ 0⤋
x = y = 0
2006-08-27 11:53:13 · answer #2 · answered by d13 666 2 · 0⤊ 0⤋
2x+2y=o is 1 st equation
let 2nd be written like this y=4x+0 as -4x+0y=0
solve Ist and second equations
we get X=0 and y=0
2006-08-27 10:53:57 · answer #3 · answered by pavani 2 · 0⤊ 0⤋
First we need to get both variables on the left side.
2x + 2y = 0
-4x + y = 0
Now we need to multiply a equation by a number so that when we subtract (or add), one of the variables will cancel out. We are going to multiply the second by equation by 2 so the 2y from the top equation will disappear when we subtract the 2y from the lower equation.
2x + 2y = 0
2(-4x + y) = (2)0
So we have:
2x + 2y = 0
-8x + 2y = 0
We subract the bottom from the top and get:
10x = 0
Therefore,
x = 0
If you plug x in the original equation you will also find that
y = 0
2006-08-27 08:08:50 · answer #4 · answered by Elim 5 · 1⤊ 1⤋
Re-order equation 2:
-4x +y = 0
Multiply (1) by -2
-4x - 2y = 0
subtract (2) from (1) ... -4x is eliminated ... to give 3y = 0, therefore y = 0. Since y = 0, x must also be 0 (by substituting in either of the equations).
You asked for the solution by subtraction, which is not the most efficient method, but since you asked, I have shown it in that form.
2006-08-27 08:10:32 · answer #5 · answered by Owlwings 7 · 1⤊ 1⤋
x = 0
y = 0
2006-08-27 13:18:10 · answer #6 · answered by sethivijaykumar 1 · 0⤊ 0⤋
solving first equation...
as 2x + 2y=0 , x+y=0 , x= -y ...(3)
now solving second given equation ...
as y=4x+0 ...(4) , now subsitute x=-y from equation (3) into equation (4) we have...
y= -4y+0 or,y= -4y or, 5y=0 or,y=0 ...(5)
now put equation (5) in the first given equation...
2x +2(0)=0 or,2x=0 or, x=0
RESULT: x=0 & y=0 .
2006-08-27 10:30:28 · answer #7 · answered by ifureadthisur2close 2 · 0⤊ 1⤋
Perhaps I'm wrong, but I think you copied something incorrectly here. I think y should equal 4x + some number larger than 0.
2x + 2y = 0
y = 4x + 0 so
2x + 2(4x) = 0
2x + 8x = 0
10x = 0
x = 0
2006-08-27 08:13:57 · answer #8 · answered by peter_lobell 5 · 0⤊ 2⤋
If y=4x, then 2x+2y=0 becomes
2x + 2(4X) = 2x + 8x = 10x = 0
Both X and Y are zero.
2006-08-27 08:13:54 · answer #9 · answered by Richard 7 · 4⤊ 3⤋
x=0 and y = 0 and for the future, anytime both equations are set = 0, the answer is (0,0) because both lines when graphed go through the origin.
2006-08-27 08:24:20 · answer #10 · answered by MollyMAM 6 · 1⤊ 2⤋