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You are warming up for a workout by stretching your arms out horizontally. One of your arms has a mass of 10 kg and its weight produces a torque of 30 N⋅m about your shoulder joint. What is the effective lever arm (distance from shoulder joint to the arm’s centre of gravity) of your arm?

2006-08-26 23:37:44 · 7 answers · asked by Anonymous in Science & Mathematics Physics

7 answers

sore arms ??

2006-08-26 23:44:32 · answer #1 · answered by Anonymous · 0 0

This is not a physiology question, it is a simple physics question. Paymanns is correct that the force due to gravity on a 10k object is 98 Newtons. If the torque on the object is given as 30 Newton-meters, which it is, the distance from the fulcrum to the center of gravity is 30/98, as paymanns says.

Of course, SAMI is totally wrong about living limbs not having a center of gravity (center of mass, actually, because an object need not be in a gravitational field to have such a center). Even SAMI's tiny brain has a center of mass, if you can find it (the brain, that is).

2006-08-27 00:22:12 · answer #2 · answered by ? 6 · 0 0

F=M*g=10*9.8=98 N
T=F*d=>d=30/98=0.31m
d=31 cm

2006-08-27 00:11:36 · answer #3 · answered by paymanns 2 · 1 0

The tone of shoulder muscles,the pressure of blood acting on a working limb,the friction in joints like elbow and wrist and the rotation of forearm are all forces acting about the shoulder joint. No center of gravity exists for a living limb. And a dead limb does not warm up.

2006-08-27 00:01:15 · answer #4 · answered by J.SWAMY I ఇ జ స్వామి 7 · 0 1

Sorry cant answer that but i just go straight in their day after day working the weights and right now im pushing 60 kilo


(by the way im a woman)

2006-08-27 01:31:28 · answer #5 · answered by sawsy20 2 · 0 0

0.3m

2006-08-26 23:54:45 · answer #6 · answered by john a 2 · 0 0

huh!! dunno dude

2006-08-26 23:46:35 · answer #7 · answered by Dark Crystel 4 · 0 1

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