value of x of the equation : log(base2)cos x +log(base2 )(1-tan x)+log(base2)(1+tanx)-log(base2)sinx=1?

Question

xshould have smallest positive value

Answer 1

Use log rules:

log(A) + log(B) = log(A*B)

so your equation becomes:

log(base2) [ [cos x(1-tan x)(1+tanx)]/sin(x)] = 1

remove the log by raising both sides to 2nd power

[cos x(1-tan x)(1+tanx)]/sin(x)] = 2

Expand this:

1 – tan²(x) = 2tan(x)

Rearrange:

tan²(x) + 2tan(x) – 1 = 0

let u =tan(x)

u²+ 2u – 1 = 0

solve this quadratic:

u = -1 ± √2

so:

tan(x) = -1 ± √2

x = tan ˉ¹ ( -1 ± √2)

x = 67.5 degrees
or
x = -22.5 degrees




Also, Doug if you place your mouse cursor over the ellipses, the rest of the equation becomes visible.

Answer 2

in basic terms interior the shrink that's authentic. As x tactics infinity the functionality a million/x tactics 0. in basic terms in a theoretical situation x could be infinity. In prepare one assumes that this functionality is 0 for massive values of x (relative to universal values of the gadget in query). i wish this helps.

Answer 3

Would it be too much to ask for the entire equation? It really would help. A **lot** ☺


Doug

Answer 4

me no know
LOL!!!!!!
i didnt understand the question

Answer 5

not in my subject