8yrs.ago melanie was twice asold as roger nowthe sum of their age is no more than 41.at most how old is roger?

Question

problems on linear inequalities

Answer 1

Older than he was before.

Answer 2

Lets try again people

x= melanie
y= roger

8yrs.ago melanie was twice asold as roger now the sum of their age is no more than 41.at most how old is roger?


x-8 = 2y

x + Y <= 41

solve for x

x = 2y + 8

3y + 8 <= 41
3y <= 33

y=11
x=30

Melanie is 30 (or less)
Roger is 11 (or less)

these are the maximum ages
and their combined age is no more than 41

Answer 3

I am not at all sure if this is right...it's been a darn long time.

If melanie's age = x, and roger = y

x + y and
x-8 = (y-8)2
then solve equation for x

x = 2y - 16 - 8 or x = 2y - 24

then substitute: (2y - 24) + y or
3y -24 3y -24 + 24 3y 3y/3 y
Is it supposed to be in whole numbers? I'd say 22.

Answer 4

8 years before:
melanie was twice (2y years)as old as roger (y years)
so, 2y+8 is the age of melanie and y+8 is the age of roger present.As given,
2y+8+y+8=41=40 (as given-no more than 41.)
3y+16=40
3y=40-16
3y=24
y=8
age of roger=y+8=8+8=16
age of melanie=2y+8=2*8+8=24

Answer 5

Eight years ago melanie was 8 and roger was 16. Now melanie is 16 and roger is 24. Roger is 24

Oooops had it backwards. Roger is 16

Answer 6

the answer is 21
13+26=39 whichi no more than 41
roger's age was 13 years old 8 years ago
13+8=21 age of roger

Answer 7

25 years

Answer 8

X was the age of Ro 8 years ago. Me was 2X
now the ages of Ro & Me are X+8+2X+8=41
X=8, X+8=16

Answer 9

Roger's age = x
Melanie's = y

So, y-8 = 2(x-8)
x+y<=41

So, 2x-y=8
x+y<=41
Let x+y = 41

So, 3x = 49

So, x is almost 16.

Answer 10

age of roger=(8+25/3) yrs
=16.3333 yrs.(upto four decimal places)
if needed it can b converted exactly into months,days,hours,minutes and seconds to b more precise.

Answer 11

25 ... wait 41-25=16