Solution A being CuSo4 and Sol.B would be NaOh.
In the Test procedures, it said that the 2 solutions should be kept in separate bottles until used.Now we have to answer why?Anyone,help?
2006-08-26 21:36:27 · 5 answers · asked by ariane 1 in Science & Mathematics ➔ Chemistry
CuSO4+2NaOH=Na2SO4+Cu(OH)2
if they are toghter we have other compounds.and we cant use them.
2006-08-26 21:51:24 · answer #1 · answered by ferry 2 · 0⤊ 1⤋
what the others said is true, partially. Indeed a precipitate would form :
CuSO4 + 2*NaOH -> Na2SO4 + Cu(OH)2
But we could still use the solution for our tests right away. Problem is that in time, Cu(OH)2 discomposes to form CuO. Also, complex compounds may occur, that would interfere with the fehling test
2006-08-27 05:58:44 · answer #2 · answered by andreicnx 3 · 0⤊ 0⤋
CuSO4 is a stable solution. NaOH is a stable solution . Mixed, they react. You want the reaction when you do the test.
2006-08-27 13:07:57 · answer #3 · answered by science teacher 7 · 0⤊ 0⤋
If they are mixed Cu(OH)2 will form and precipitate out.
2006-08-27 05:10:33 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 1⤋
because they might explode if keep them near each other.
2006-08-27 04:40:38 · answer #5 · answered by merdad b 2 · 0⤊ 2⤋