Which is the correct one? Or are both of them the same?
Zn0 + Na0H= Na2Zn02 + H20
and
Zn0 + Na0H= [Zn(OH)4]2- + 2 Na+
and pliz gimme the reason why ok?
thanks
2006-08-26 21:11:27 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Apart from the fact that the equations aren't balanced, you need to state whether you are working in aqueous solution (that would be b) or in a melt (a).
2006-08-26 22:05:54 · answer #1 · answered by jorganos 6 · 0⤊ 0⤋
If zinc oxide reacted with sodium hydroxide the equation would be:
ZnO +2 NaOH ---> Zn(OH)2 +2 NaO
THen the soduim oxide would react with the water present to make more NaOH
I do not have a table with me to check the solubility of zinc hydroxide.
2006-08-27 13:24:41 · answer #2 · answered by science teacher 7 · 0⤊ 0⤋
ZnO+NaOH=(ZN(OH)4)2-+2Na
this is not true,because in side 2Na and other side Na
and first is incorrect.
2006-08-27 04:25:03 · answer #3 · answered by ferry 2 · 0⤊ 0⤋
Balance them.
2006-08-27 05:10:40 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋
something is wrong in ur equation
2006-08-27 07:20:19 · answer #5 · answered by Navdeep B 3 · 0⤊ 0⤋
both of them are wrong
2006-08-27 04:33:42 · answer #6 · answered by merdad b 2 · 0⤊ 0⤋