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a^(n)-b^(n)
=(a-b)^(n)+nk(a-b)
here when "a" is an odd natural number , "b" is any natural number other then "a" and "n" is any prime number or its factors are the same prime (the numbers whose multiples are 5 like 25 ,125 etc are excluded but the case of 5 is included.) then "k"will always be a natural number.
give an example to prove it wrong.

2006-08-26 18:33:11 · 3 answers · asked by rajesh bhowmick 2 in Science & Mathematics Mathematics

3 answers

This does not have any counter example as this is mathemetically correct.
to prove it let a = (b+c)

a^n - b^n
= (c+b)^n - b^n
using bionomial theorerm
the 1st is sum of n+1 terms kth term is
n
C c^k*b^(n-k)
K
when k =n the last term = b^n which cancells

ther 1st term = c^n
all other terms are multiple of n and c so can be added to give your expression by choosing suitable K

so it is true for all cases for suitable k

2006-08-27 18:16:48 · answer #1 · answered by Mein Hoon Na 7 · 0 0

no there is no example that it is wrong.

any expression with natural numbers that only uses the operator + - * ^ results in a natural number.

So if you have equality then K has to be a natural number, sinse the lft side is a natural number.

2006-08-27 01:45:05 · answer #2 · answered by gjmb1960 7 · 0 1

me no understand ur question

2006-08-27 06:09:47 · answer #3 · answered by Navdeep B 3 · 0 0

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