Alawn mower is pushed with a force of 42 newtons along the handle at 38 degrees with the lawn.In mowing?

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Alawn mower is pushed with a force of 42 newtons along the handle at 38 degrees with the lawn.In mowing?

the lawn mower is pushed over a tatal horizontal displacement of 0.800 km.What is the x-component of force?How much work is done?

2006-08-26 17:50:02 · 3 answers · asked by xxgodsgift2youxx 1 in Science & Mathematics ➔ Physics

3 answers

x component is 42newtons times cos 38 degrees=34.7 newtons. Work done= 34.7 newtons times 800 metres=27760 joules.

2006-08-26 18:03:48 · answer #1 · answered by zee_prime 6 · 0⤊ 0⤋

The x-component of the force would be calculated by using

Fx= Fcos(38)

as for the work done, assuming it's constant force and not going all over the place then it'd just simply be

W=(Fx)d

where d would be your 0.8 km

2006-08-27 00:57:55 · answer #2 · answered by seikenfan922 3 · 0⤊ 0⤋

x={42[cos(38)]}
work done=0.800x

2006-08-27 01:00:20 · answer #3 · answered by straightshooter 5 · 0⤊ 0⤋