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A circle C1 with centre O1 exists. Inside it exists another circle C2 with centre O2 just touching C1 at A.Another circle C3 ,passing through O2 also touches C1 at B meeting C2 at P and Q a line through PQ touches C1 at X and Y.X and Y are joined to B meeting C3 at F and G respectively.Prove that FG is tangent to C2
Please no co ordinates or trignometry

2006-08-26 17:23:20 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

Here a tangent is a line touching a circle at a point

2006-08-26 18:06:01 · update #1

sorry about a line through X and Y.I meant a line joining X and Y

2006-08-26 18:07:37 · update #2

to Benjamin_N
Thats a good conclusion but I figured it out looooong ago

2006-08-26 18:28:35 · update #3

6 answers

I might be able to help, but I need some clarification on what "X and Y are joined at B meeting C3 at F and G" means. X and Y are points. By your definition above, a line through X and Y only intersects C3 at P and Q.

2006-08-26 17:33:46 · answer #1 · answered by Will 6 · 2 0

( stares wide eyed drooling slighty) dude hold on i think i can do this tell what the chapter is your working on like so i can get a category and then i will get the answer and edit my thingy

There are two definitions of tangent in geometry: First, a tangent line is a line that touches a curve at one point, but does not cross the curve. Both curves and straight lines can be tangent to another curve.

A tangent to a circle is perpendicular to the radius drawn to the point of tangency. You will find a good proof of this in your geometry book. The diagram is too difficult for me to draw here.

In a right triangle, the tangent of an angle is the ratio of the side opposite the acute angle to the side adjacent. Remember, a right triangle has two sides and an hypotenuse.

ok so bsed on that i could say that ummmm yeha i still dont know i am taking geometry but let me explain my teacher told us he was the only teacher that could count three weeks because every other teacher gave us our three weeks grade a girl got out a calender and showed him that it had been three weeks and he said yeah ill remember that next time i grade your test if that says anyting about his character he tells us the page to work we dont learn anything or i would try to help more i really am sorry that you have to do that problem that sucks toads

2006-08-26 17:31:10 · answer #2 · answered by anne 2 · 0 0

Well, for starters, FG || PQ because of similarity. So that establishes that FG is perpendicular to the radius of circle #2. This will be true even if circle #3 does not pass through the center of circle #2, so the remaining thing to prove--the distance from the center of circle #2 of this intersection--has to do with the special requirement on circle #3.

Well, one more comment on this before I retire. The locus of all the possible centers for circle # 3 seems to be an ellipse with foci at O1 and O2, with the distances from center 3 to these points always adding to R1. Good luck, and good night.

2006-08-26 18:24:18 · answer #3 · answered by Benjamin N 4 · 0 0

Draw it out and read the last chapter of your geometry book doing all sample problems.

2006-08-26 17:37:03 · answer #4 · answered by DrB 7 · 0 0

Show us the diagram!

Give us a link to the diagram.

2006-08-26 17:30:39 · answer #5 · answered by Anonymous · 0 0

Sorry i barely passed that class last year. I can't help.

2006-08-26 17:26:51 · answer #6 · answered by Bubbles Will Rule the World!!!!! 4 · 0 1

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