Is there a formula? Can anyone tell me if there's any way to do it on my calculator (TI-83 Plus)?
btw it is the kind of graph where x doesn't ever reach 0 and y doesn't reach 0 too. forgot what that is called.
2006-08-26 15:51:21 · 5 answers · asked by -WANTED- 3 in Science & Mathematics ➔ Mathematics
to clarify things a little, it is kind of like a L shape graph.
2006-08-26 17:55:53 · update #1
The graph that you are describing is the basic graph of the function y= 1/X. Depending on what points ur graph goes through will determine what transformations your graph shall have. The basic graph of 1/x neva touches the y-axis nor the x-axis at 0. You will know what the equation is by using the transformational techniques you learned in precalculus such as x-axis reflection, horizontial shift, vertical shift, strecthing and shrinking.
2006-08-26 19:10:37 · answer #1 · answered by Andre R 1 · 0⤊ 0⤋
One way is to find the slope and y-intercept of the graph, then write the equation in slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept). To do this, you only need two point.
Pick two points on the graph. Since I don't know the specific points on your graph, I will call them (x1, y1) and (x2, y2).
To find the slope, simplify the following fraction:
(y2 - y1) / (x2 - x1)
When finding the y-intercept, realize that it is the same for the entire graph. To find it, we substitute the x-value and y-value of one point on the graph into the slope-intercept formula and solve for b:
y1 = m(x1) + b
y1 / (m*x1) = b
where m is the slope we found earlier.
As for the kind of graph where x never reaches 0 and y never reaches, I don't think it has a particular name. There are an infinate number of graphs where x and y never reach 0. Think of a parabola where the ends go towards positive infinity (or point up) and the vertex is above the x-axis. Perhaps I am unclear about what you are talking about.
2006-08-26 23:08:48 · answer #2 · answered by dramaman22 3 · 0⤊ 0⤋
Yes, you can. It's called 'curve fitting'. And there are a *ton* of formulas. But you have to decide what kind of function you want to 'fit' your data points onto.
The Fundamental Therom of Algebra guarantees that if you have n points, you can always find at least one polynomial (of order n-1) that will pass through all of them.
Doug
2006-08-26 22:59:46 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
On the Cartesian plane
sin = y / r
cos = x / r
tan = y / x
2006-08-27 00:14:06 · answer #4 · answered by Kevin H 7 · 0⤊ 0⤋
i dont know.......
are u sure u can use tha calculator........
is suggest try n devise ur own function which satisfies all points on the graph..........
2006-08-26 22:57:42 · answer #5 · answered by monkey see monkey do! 3 · 0⤊ 0⤋