V=x(4-2x)(6-2x) what is the answer?

Answer 1

V = x(4-2x)(6-2x) =
if V=0
so we have :
x (4x-2x)(6-2x)=0

x=0 ; V= 0
OR
4x-2x=0 ;2x=0 ; x=0
OR
6-2x=0 ; -2x=-6 ; x= (-6/-2) ; x= +3 ; V= 3(4-2*3)(6-2*3) = 0

{ V=x(4-2x)(6-2x) = x*[ (4*6 - 4* -2x) + (-2x *6 + (-2x)(-2x))]
x [ 24 + 8x -12x + 4x^2 ]= x ( -4x^2 -4x+24)
-4x^3 - 4x^2 + 24x }

Answer 2

V=x(4-2x)(6-2x)
V=(4x-2x^2)(6-2x)
V=24x-8x^2-12x^2+4x^3
V=4x^3-20x^2+24x

Answer 3

V=x(4-2x)(6-2x)
=x[24-8x-12x+4x^2]
=x[4x^2-20x+24]
=4x[x^2-5x+6]
=4x[x(x-6)-1(x-6)]
=4x[(x-6)(x-1)]
sorry, couldn't solve it further, but what is the value of V? I mean, its impossible to solve for any nounafs without knowing all the other variables.

Answer 4

V = 4*x*(2 - x)*(3 - x)

V + (20*(x^2)) - (4*(x^3)) - (24*x) = 0

Answer 5

V is the volume of a cube having dimentions interrelated and one dimention x should be lesser than 2 units.

Answer 6

4x^3 - 20x^2 + 24x - v = 0

Answer 7

v=24x+4x(squared sign [little 2 above number])

im jsut starting algebra 2

Answer 8

4x.x(7-5x) i am not good in maths calculation.LIFE is also like this you have good thing in mind to go but situation as a main factor changes the result.

Answer 9

V= 8x

Answer 10

4(x*x*x)-20(X*x)+24x=0