3(n+1)! divided by (over) 5n!
2006-08-26 11:24:33 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(n+1)! = (n+1)(n!)
3(n+1)!/(5(n!))
= 3(n+1)(n!)/(5(n!))
n! cancels
= 3(n+1)/5
2006-08-26 11:31:25 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
I am not 100% of the syntax here, is it 5 * (n!) of (5n)!?
If the later then it cannot be simplified. If the former, then
3 (n+1)! is equal to 3 * (n+1) * n!
and 3 * (n+1) * n! / ( 5 * n!) is equal to 3 (n+1) /5
or (3n+3)/5
2006-08-26 18:32:37 · answer #2 · answered by Vincent G 7 · 0⤊ 0⤋
Well, (n+1)!/n! is the same thing as n. So that means the whole fraction is 3(n+1)/5.
2006-08-26 18:30:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Note that (n+1)! = (n+1)*n!
You do the rest
2006-08-26 18:31:36 · answer #4 · answered by banjuja58 4 · 0⤊ 0⤋
it 3n+1/5n, that's it, nothing else you can do
2006-08-26 19:07:21 · answer #5 · answered by Khalil S 3 · 0⤊ 0⤋