thnx for ur help =]
2006-08-26 11:22:49 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
e^(3 ln x) = e^3 * e ^ ln x
e ^ ln x = x
= x * e^3
there you go
2006-08-26 11:31:45 · answer #1 · answered by Chris M 2 · 0⤊ 0⤋
the answer is x^3. you simplify is by seeing the 3 ln (x) is actually ln x^3. and then e and ln are opposities of each other so they cancel out. then, all you have remaining is x^3
2006-08-26 11:28:04 · answer #2 · answered by jgrdino 2 · 0⤊ 0⤋
by log rules if an outside number is a coefficient of the log like 3.ln x,
this is the same as ln (x^3)
so e^(3.ln x) = e^[ln (x^3)]
= x^3
voila.
2006-08-27 02:52:06 · answer #3 · answered by yasiru89 6 · 0⤊ 0⤋
3 ^ x, since the natural log of x ^ 3 cancels out the with its antilog.
2006-08-26 11:29:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋
e^(3 lnx) = (e^lnx)^3 = x^3
2006-08-26 11:29:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
e^(3ln(x))
e^(ln(x^3))
x^3
2006-08-26 12:02:42 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋