Jim can fill a pool carrying bucks of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
2006-08-26 08:33:02 · 6 answers · asked by entalee 2 in Science & Mathematics ➔ Mathematics
1
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1/30 + 1/45 + 1/90
=15 minutes
2006-08-26 08:38:03 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
Jim fills 1/30 of the pool in a min. Sue fills 1/45 of the pool in a minute. Tony fills 1/90 of the pool in a minute. Together they would fill 6/90 in a minute. (1/30+1/45+1/90) 6/90 is equal to 1/15. so it would take 15 minutes
2006-08-26 15:40:59 · answer #2 · answered by upinbubbles 2 · 0⤊ 0⤋
Jim's 1 min work = 1/30
sue's 1 min work = 1/45
tony's 1 min work = 1/90
job done altogether is
= 1/30 + 1/45 + 1/90
= (3 + 2 + 1)/90
= 6/90
= 1/15
therefore time taken to complete the job by the three together is 15 minutes
2006-08-26 15:45:04 · answer #3 · answered by pappu 2 · 0⤊ 0⤋
what do they teach you at that school...i mean how old are you??OMG
jim....1 minute....fills 1/30 of the pool
sue....1 minute....fills 1/45 of the poll
tony....1 minute fills 1/90 of the pool
so ...in 1 minute....they fill 1/30+1/45+1/90 of the pool
this is 1/15 of the pool
so....x minutes 15/15 of the pool if 1 minute....1/15 the result is 15 minutes
...........so you don't die stupid
2006-08-26 15:55:03 · answer #4 · answered by suzanna_banana 3 · 0⤊ 0⤋
55 minutes
2006-08-26 15:38:44 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Suzana, ai grija ce zici despre banana...
2006-08-27 07:43:15 · answer #6 · answered by feiervlad 2 · 0⤊ 0⤋