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Adult tickets for a play cost $11 and child tickets cost $10. If there were 23 people at a performance and the theater collected $246 from ticket sales, how many children attended the play?

Thank you for your help. I have only one more week left in my algebra course and I'm just trying to get through it as best as I can. It has been really hard for me.

2006-08-26 05:30:08 · 9 answers · asked by sistermoon 4 in Education & Reference Homework Help

9 answers

let number of adults be x
let number of children be y
total = 23 people .,
i.e x+y = 23
i.e 11x+11y =253
given that
11x + 10y = 246 ( cost of tickets)
y = 253 - 246 = 7
so number of children = y = 7

2006-08-26 05:39:35 · answer #1 · answered by emperor 1 · 1 0

Let a be the number of adult tickets sold, and c for children tickets sold. You create two systems:

a + c = 23 (for the people attending)
11a + 10c = 246 (for the money made)

Solve the system for each variable. Hope that helps!

2006-08-26 05:35:44 · answer #2 · answered by Link 5 · 0 0

I'll help you set it up. Lets say the number of adults is "a" and the number of children is "c". So 11a + 10c = 246. Since 23 people were there, then a + c = 23. Use substitution to finish the rest.

2006-08-26 05:38:00 · answer #3 · answered by banjuja58 4 · 0 0

x is the number of children.
So there must be 23 - x adults.

Money collected from the children 10x dollars
Money from the adults is 11(23-x)

Total money 10x +11(23-x) and this must be 246 dollars.

10x +11(23-x)=246
10x + 253 -11x = 246
253 -x = 246
253 - 246 = x
x (number of children) = 7
Greatings from Greece

2006-08-26 05:38:25 · answer #4 · answered by lykovetos 5 · 0 0

let no of adults =a & no of child =c

then total no = 23 so a+c =23 -------------(1)
total money =246 so (11*a) +(10*c) =246 so 11a +10 c =246---(2)

now two eqn two unknown so
Eqn(2) - 10*eqn (1)

(11a+10c )-(10a+10c) =246-(10*23)

so a=16
hence c=7


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2006-08-26 05:41:24 · answer #5 · answered by Kamal Wadhwani 1 · 0 0

Basic way (using one variable)

Let adults=a
then children=(23-a)
Equation: 11a + 10(23-a)=246
simplify: a+ 230=246
a=16
16 adults
7 children

2006-08-26 05:58:09 · answer #6 · answered by maverick 3 · 0 0

16 adults and 7 children

2006-08-26 05:34:36 · answer #7 · answered by larrythemonkey22 1 · 0 0

If the scholars contemporary grade is a ninety% then we’re of course assuming it’s out of a hundred% ninety/a hundred Now because of the fact the scholars grade greater 20% from the final grading era then you certainly upload that to the previous a hundred% offering you with ninety/ one hundred twenty = .seventy 5 and because grades are in probabilities you multiply .seventy 5 by a hundred offering you with seventy 5% because of the fact the scholars previous grade

2016-12-11 15:45:05 · answer #8 · answered by hirschfeld 4 · 0 0

ummm... i don't know..... but shouldnt you be working it out by yourself

2006-08-26 05:33:05 · answer #9 · answered by Anonymous · 0 1

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