5 years ago a man was 7times as old as his son.5 years hence the father will be 3 times as old as his son.find

Question

5 years ago a man was 7times as old as his son.5 years hence the father will be 3 times as old as his son.find their present ages?

Answer 1

All right. So...

x = man's present age
y = son's current age

7(y-5)=x
3(y+5)=x

Set them equal to one another...

7(y-5)=3(y+5)

After multiplying and simplifying, you will get:
4y=50

The son's age is 12.5 years. The fathers age (substitute into the original system) is 52.5 years.

Answer 2

The dad is 40, and the son is 10.
d=7s (the dad and son five years ago)
and
d+10=3(s+10) (the dad and son five years from now)
d+10=3s+30
substitute in the value of d from the first equation
7s+10=3s+30
rearrange
7s-3s=30-10
4s=20
s=5
Note this is the son five years ago...
so the son is now 10
the dad five years ago = 7s = 35, so the dad is now 40

now check your answer,
five years ago, the son was 5 and dad was 35
5*7=35 Check :)
Five years from now, the don is 15, and the dad is 45
15*3=45 Check :)

Answer 3

The boy is 10 and the dad is 40. I had to get my husband to answer this one, as he is the math nut.
x-5=7 5 is the boy's age, the -5 and +5 cancel each other
x+5=3
2x=10
Hope this helps! Good luck.

Answer 4

I take it you mean "5 years later" (ie 2 years in the past) fairly than "5 years from now" in view which you're writing the two interior the previous stressful. subsequently: m - 7 = 5(s-7) = 5s - 35 ==> m = 5s - 28 m - 2 = 3(s-2) = 3s - 6 ==> m = 3s - 4 Subtract: 2s = 24, so s = 12 and m = 32

Answer 5

The boy is 10 and his father is 40

Answer 6

before the son was 5 and the man was 35 ....
right now they are 10 and 40
in 5 years they will be 15 and 45\