2006-08-26 00:43:13 · 8 answers · asked by RGs 1 in Science & Mathematics ➔ Physics
Are there any expreimental proof for the answers
2006-08-27 20:25:34 · update #1
Ignoring the unpredictable effects (such as scraping some of the metal from the socket when you remove the bulb, and dust accumulation) the weight should stay the same. Some of the filament evaporates (or sublimes) and condenses onto the glass envelope, and some of the filament may combine with the gas, if any, inside the bulb, but these are transfers of mass within the bulb; nothing escapes it.
2006-08-26 00:51:29 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋
Sure, it will be the same. The only difference would be the filament, which evaporates as the bulb burns (that's why they burn out). But you will not lose the mass of the evaporated filament, because it's sealed inside the bulb.
Of course, if the bulb breaks it will weigh less, obviously.
2006-08-26 08:28:53 · answer #2 · answered by poorcocoboiboi 6 · 0⤊ 0⤋
yes .Ther is no possibility of sny addition of deduction to its weight , even if some combustion has happened inside (though not posible ) , since the the bulb is tightly closed and is njot broken.to let outside air to get into it.
2006-08-26 09:57:46 · answer #3 · answered by Infinity 7 · 0⤊ 0⤋
decreases in weight sometimes since the ink used by lamp manufacture for logo/specification evaoporates during the long life.
2006-08-28 04:23:45 · answer #4 · answered by A Bank 1 · 0⤊ 0⤋
yep, its exacly the same, as long as no mass is lost or gained externally.
2006-08-26 08:19:35 · answer #5 · answered by phychic! 2 · 0⤊ 0⤋
It will increase.
2006-08-26 07:50:03 · answer #6 · answered by ag_iitkgp 7 · 0⤊ 0⤋
well that's a diffrent ? got no idea.
2006-08-26 07:48:55 · answer #7 · answered by Anonymous · 0⤊ 0⤋
no
2006-08-26 07:46:43 · answer #8 · answered by ASHISH R 1 · 0⤊ 0⤋