how do you find the instantaneous velocity?

Answer 1

Instantaneous velocity is obtained with calculus. it is

v = dx/dt.

You must find the time-derivative of x(t) at the instant (value of t) you want the instantaneous velocity.

Answer 2

v(t) = (1/m)*integral(0,t,f(a)da) + v(0)

where m is an objects mass

f(t) is a force applied in line with the objects center-of-mass. And "a" is simply a variable of integration


For 2, 3 or higher dimensional cases, just compute the above integral in each dimension separately, for example, in the 3D case:

vx(t) = (1/m)*integral(0,t,fx(a)da) + vx(0)
vy(t) = (1/m)*integral(0,t,fy(a)da) + vy(0)
vz(t) = (1/m)*integral(0,t,fz(a)da) + vz(0)
v(t) = sqrt(vx(t)^2 + vy(t)^2 + vz(t)^2)

where vx(t), vy(y) and vz(t) are the velocities in the x,y, and z directions respectively, and v(t) is the total velocity.

Answer 3

simply put, it's the velocity in a very short amt. of time...lower the delta t and you'll get closer to instantaneous.

Answer 4

i assume you've been given a time dependent function that describes the position or the acceleration of this problem?

you might include those details in the next version of your question.

Answer 5

take the derivative

Answer 6

v= dx/dt