1.Solve the equation 3m^2+6m=3 using the quadratic formula.
A. x = -6 There is only one root to this equation.
b. x = 2.5 and -14.5
c.x = .414 and -2.414
Please have tried this but cant get it.
2006-08-25 13:44:44 · 5 answers · asked by joe j 1 in Education & Reference ➔ Homework Help
First, you have to simplify the equation:
3m^2 + 6m = 3
3m^2 + 6m - 3 = 0
m^2 + 2m - 1 = 0
Use the quadratic equation to solve for m, where a = 1, b = 2 and c = -1.
m = -2 +- [2^2 - 4(1)(-1)]^1/2
. . . . . . . . . . .(2) (1)
m = -2 +- (4 + 4)^1/2
. . . . . . . . 2
m = -2 +- (8)^1/2
. . . . . . . . 2
m = -2 +- 2(2)^1/2
. . . . . . . . 2
m = -1 +- 2^1/2
The square root of 2 is equal to 1.414.
m = -1 + 1.414 = .414
m = -1 - 1.414 = -2.414
The answer is c.
2006-08-25 13:59:17 · answer #1 · answered by lemons 3 · 0⤊ 0⤋
Try m = -b +- (b^2 -4ac)^1/2 / 2a
Answer is c.
Remember, c in the quadratic formula is -3, not +3.
so, m = -6 +- sqrt(6^2 - 4(3)(-3)) / 2 (3)
2006-08-25 20:50:59 · answer #2 · answered by Simple 7 · 1⤊ 0⤋
Discussion of the quadratic formula is indeed correct. The final solution is c
x = -1 +/- sqrt(2) sqrt = square root
x= -1 +/- (1.414)
x = -2.414 and x = 0.414 (x represent the 0s of the equation)
QED.
2006-08-25 21:08:10 · answer #3 · answered by alrivera_1 4 · 0⤊ 0⤋
The answer is c
if you have a quadtric equation of the form:
Ax^2 + Bx + C = 0
x = -B + sqrt(B^2 -4AC)/(4AC)
and x = -B - sqrt(B^2 -4AC)/(4AC)
Plug and chug.
In your case, A=3, B = 6, C =-3
2006-08-25 20:49:27 · answer #4 · answered by gtn 3 · 1⤊ 0⤋
That is so confusing.How old are you to have homework so hard?
2006-08-25 20:47:52 · answer #5 · answered by Anonymous · 0⤊ 2⤋