help math Please. please.?

Question

Having trouble dont understandthis?
For problems 1-2 write the value of the discriminant of each equation, decide how many different real-number roots the equation has, and determine how many points the parabola will intersect with the x-axis. Do not solve the equation.
1.x^2+7x+9=0
A.discriminant is 13, indicating only one real root, with the parabola intersecting the x-axis at only one point
B.discriminant is 13, indicating there are two real roots, with the parabola intersecting the x-axis at two points
C.discriminant is 13, indicating there are two real roots, with the parabola intersecting the x-axis at only one point, (13, 0)

2.2x^2+5x+7=0
A.discriminant is -31, indicating there are two real roots, with the parabola intersecting the x-axis at two places
B.discriminant is -31, indicating there are two real, negative roots, with the parabola intersecting the x-axis at two places. C.discriminant is -31, indicating there are no real realr

C. should say discriminant is -31, indicating there are no real roots, with the parabola not intersecting the x-axis at all

Answer 1

I recommend either 1 or 2:
1. get a tutor
2. FInd a math geek

Answer 2

1. A
the discriminant's value is given by b^2 - 4ac. a=1, b=7 and c=9. solving that, you get 49 - 36 = 13. since it is not equal to zero, the graph touches the x-axis at two points. (not being equal to zero indicates that there are two real roots, as long as the discriminant is positive.)
2. C
if the discriminant is negative, that means that the equation has imaginary roots (remember, there is no such thing as a square root of a negative number!). an equation with imaginary roots does not touch the x-axis. -31 is given by the formula b^2 - 4ac.

Answer 3

sorry but HELLLLLLLL NO im not going to read and solve all that,,i just want 2 points lol