Math Question i need help on..?

Question

The last week of a month a car dealership sold 12 cars. A new sales promotion came out the first week of the next month and the sold 19 cars that week. What was the percent increase in sales from the last week of the previous month compared to the first week of the next month?

58%
119%
158%
175%
200%
???

Answer 1

The increase is 7 cars (19-12). 7/12 (you divide by 12 since 12 is your basis for comparison) is 0.58333, expressed in % that is 58.3%

Answer 2

The increase would be (19-12)/12 = 7/12, which is less then 1 so you can eliminate everything besides 58%... and without knowing for sure on a calculator, I believe 7/12 would come out to something like 0.583333...

Answer 3

You subtract 19-12 to get the increase then you always divide by the first number in the problem which is 12. 7/12 = .5833333.....which would be your 58% answer

Answer 4

Let x% = the percent increase of sales
p = price of one car:

Thus,
12p = sales on the last week of the previous month
19p = sales on the 1st week of the next month
19p - 12p or simply 7p = the increase in sales

since 7p is the amount of increase in sales, then 7p is x% of 12p. In symbols,
7p = (x%) · (12p)

Divide both sides by 12p
7p/(12p) = (x%) · (12p)/(12p)

On the left, you can cancel out the p. and on the right, you can cancel the 12p.
7/12 = x%
x% = 7/12
x% = 0.583333333333333333333333333333333333333333
x% = 58.33333333333333333333333333333333333333 %
x% ≈ 58.33%
x% ≈ 58%

^_^

Answer 5

19-12=7 or 7/12

Divide 7 by 12 which equals to 58.3% repeating. If you round it, you get 58%.

Answer:58%