i still dont know how to do the height of an equilateral triangle as a function of its side length.
i need help on how to do domain and range of y=cubed root of quantity x-3
y=x^2/3
2006-08-25 13:07:42 · 4 answers · asked by josh 2 in Education & Reference ➔ Homework Help
Let the side length of the triangle be x.
1/2 of the side length will be x/2.
Let the height of the triangle be h.
h^2 + (x/2)^2 = x^2
Solve for h. I am utilising Pythagorus theorem.
Domain of y = x^1/3
x : all real numbers
Range : y stretches from 0 to infinity, ie. all non-negative real numbers
2006-08-25 13:16:23 · answer #1 · answered by Simple 7 · 0⤊ 0⤋
Height of triangle as fnctn of side lengh:
h(x) = (sqrt3/2)x (used 30-60-90 triangle)
If y = (x-3)^(1/3), the domain is all real numbers, and the range is also all reals.
2006-08-25 13:15:47 · answer #2 · answered by jenh42002 7 · 0⤊ 0⤋
The answer is 3...
2006-08-25 13:14:33 · answer #3 · answered by maverick21000 2 · 0⤊ 0⤋
sorry, no idea.
2006-08-25 13:13:36 · answer #4 · answered by Iamsocool 3 · 0⤊ 1⤋