the paparazzis? i heard she hit 2 of them, why?
That happened in Argentina? Because of Gael Garcia Bernal?
I cant bellieve that of Natalie.
Could someone please inform me what really happened?
ty!!
2006-08-25 09:44:12 · 9 answers · asked by Anonymous in Entertainment & Music ➔ Celebrities
Natalie Portman....she can act...(except in Star Wars...no matter how much I love it...I admit...they can't act)....watch her in Garden State and V for Vendetta...you'll love her.....and I think Keira Knightley is over rated and Natalie Portman has actually got a brain.....and Natalie Portman hitting to of them?..sounds impossible...but Gael Garcia Bernal is hot....lol..I'd do anything for him...
GO NATALIE PORTMAN....yeah..so that's obvious...
2006-08-25 10:13:13 · answer #1 · answered by Leia Skywalker 4 · 0⤊ 0⤋
How is this even a question? Keira Knightley all the way.
2006-08-25 17:03:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
portman hands down - keira looks like a chicken just skin & bones how in the world can anyone thinks she's hot
2006-08-25 21:04:55 · answer #3 · answered by r.j, 3 · 0⤊ 0⤋
she was attacked by more than one photographer, Natalie is the sweetest chick on the planet, but those paparazzi in argentina are way too violent...this is the vid: http://youtube.com/watch?v=tTJGROj5cXg
2006-08-27 01:28:44 · answer #4 · answered by eduardo l 2 · 0⤊ 0⤋
Kiera Knightley every time. She's delicious. Natalie is very nice but .....
2006-08-25 16:49:24 · answer #5 · answered by quatt47 7 · 1⤊ 0⤋
keira. her accent.
if natalie did hit someone, they're the paparazzi, they don't qualify as human beings.
2006-08-25 16:52:15 · answer #6 · answered by Anonymous · 1⤊ 1⤋
Keira Knightly I'm not sure why though.
2006-08-25 16:50:40 · answer #7 · answered by Laela 2 · 1⤊ 0⤋
They look exactly alike. So I like them both. I think they are both great actresses in their own way.
2006-08-25 16:51:38 · answer #8 · answered by Anonymous · 0⤊ 0⤋
both...i'd do them anytime lol
2006-08-25 16:53:38 · answer #9 · answered by Jus call me "BUBS" 3 · 0⤊ 0⤋