M is the midpoint of segment AB. Find the coordinates of B given A(0,3)and M(-3,7).?

Answer 1

XM = ( XA + XB)/2
YM = (YA + YB )/2
2* [XM = ( XA + XB)/2]= 2XM = XA + XB
2* [YM = (YA + YB )/2]= 2YM = YA + YB
XB = 2XM - XA => XA=0 & XM= -3 => XB=2*-3-0= -6 ;XB=-6
YB = 2YM - YA => YA=3 & YM = 7 => YB=2*7 - 3=11 ;YB=11
B(-6,11)
HOPE I COULD GIVE YOU PREFECT ANSWER.

Answer 2

Let
(x,y) be the coordinates of B

Using the midpoint coordinates(x1/2 + x2/2,y1/2 + y2/2)

Thus,
-3 = 0/2 + x/2
7 = 3/2 + y/2

Multiply 2 to both sides of both equations
-6 = 0 + x
14 = 3 + y

Transpose
x = -6 - 0
y = 14 - 3

Simplify
x = -6
y = 11

Therefore, the coordinates of B is (-6,11)

^_^

Answer 3

Given the coordinates,

A(0, 3) and M(-3, 7)

Let the coordinates of B be (x, y).

Using Midpoint equations,

-3 = (x + 0)/2

x = -6

and

7 = (y + 3)/2

y = 11

Therefore, the coordinates of B is (-6, 11).

Answer 4

It's a straight line, so the changes in the x-y coordinates from M to B will be the same as from A to M. X went down 3 and Y went up 4, so:

A-M = (-3,4) B = M + (-3,4) = (-3-3,7+4) = (-6,11)

Answer 5

Figure that each coordinate of M is halfway from A to B. A's x-coordinate is 0, and halfway to B it's -3, so you'd need another -3 to get to B making B's x-coordinate -6. A's y-coordinate is 3, and halfway it is 7, which is a "trip" of 4 units, so 4 more units are needed to get to the end, which makes b's y-coordinate 11.

Answer 6

The coordinates of the midpoint are (xa+xb)/2 and (ya+yb)/2
So -3 = (0+x)/2 x=-6
7 = (3+y)/2 y= 11 So B(-6;11)

Answer 7

You have been reported to your teacher for trying to cheat using a mobile device. I can see you with that blackberry dude. That's so uncool - the answer is 0.8, 4.7 btw

Answer 8

-3 = (x + 0)/2
-3 = x/2
x = -6

7 = (3 + y)/2
14 = 3 + y
y = 11

ANS : (-6,11)

Answer 9

(-6,11)