Find the product :?

Question

1- Find the product : (4x - 3)(x + 8)
2- Factor : 2x^2 - 5x - 18
3- Factor : 169 - 144c^2
4- Find the square : (9 - b)^2
A- b^2 - 18b + 81
B- -b^2 - 18b + 81
C- b^2 - 9b + 81
D- b^2 + 81
10 Points for best answer Thank u

Answer 1

1- (4x - 3)(x + 8) =[ ( 4x * x) + ( 4x * 8)] + [( -3 * x) + (-3 * 8) =

4x^2 + 32X - 3x -24= 4x^2 + 29x - 24
Delta = b^2 - 4ac = 29^2 - 4*4*-24 =481+384=865
Delta = √865
x1= (-b +√Delta)/2a =( -35 + √865/ 8)
x2= (-b - √Delta)/2a = ( -35 - √865 / 8)

2- 2x^2 - 5x - 18 =
Delta = b^2 - 4ac = (-5)^2 - 4 * 2* -18 = 25-144= - 199 <0 so has no answer.

3- 169 - 144c^2 => b=0 in this factor =>
Delta= b^2 - 4ac = 0^2 - 4 * -144 * 169= 0 -97344=-97344 <0 so again has no answer.

4- (9 - b)^2
(a-b)^2= (a)^2 - (b)^2 - 2ab
if a= 9 and b=b => 9^2 - b^2 -2*9*b = 81 - b^2 - 18b OR
b^2 - 18b +81
Delta = b^2 - 4ac => (18)^2 - 4* 1* 81=324-324=0
x1= (-b +√Delta)/2a =( - (-18)+ √0 / 2*81)=18/162 ~ 0.111
x2= (-b - √Delta)/2a =( - (-18)- √0 / 2*81)= 18/162 ~ 0.111



GOOD LUCK

Answer 2

1)
(4x - 3)(x + 8)

4x(x + 8) - 3(x + 8)
=4x^2 + 32x - 3x - 24
=4x^2 - 29x - 24

2)
2x^2 - 5x - 18
(2x )(x )
(2x 9)(x 2)
(2x - 9)(x + 2)
Check:
2x(x + 2) - 9(x + 2)
2x^2 + 4x - 9x - 18
2x^2 - 5x - 18

(2x - 9)(x + 2) is the correct factoring

3) Difference of squares:
(x^2 - y^2) = (x + y)(x - y)

Apply here:
169 - 144c^2 x^2 = 169 ---> x = 13; y^2 = 144c^2 ---> y = 12c

(169 - 144c^2) = (13 + 12c)(13 - 12c)

4)
(9 - b)^2 = (9 - b)(9 - b)
=9(9 - b) - b(9 - b)
=81 - 9b - 9b + b^2
=b^2 - 18b + 81

Answer 3

----------------------------------------------------------------------------------------------------------------ILOVEYOUAndreaChristinaFabioGulle!!!
1- Find the product : (4x - 3)(x + 8)
(4x - 3)(x + 8)

Use distributive property
= x(4x - 3) + 8(4x - 3)

Use distributive property again
= 4x² - 3x + 32x - 24

Simplify
= 4x² + 29x - 24

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2- Factor : 2x² - 5x - 18
2x² - 5x - 18

= (2x - 9)(x + 2)

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3- Factor : 169 - 144c²
This is an example of the difference of 2 squares. Its factor is the product of the difference and the sum of the square roots of both factors.
169 - 144c²
= (13 - 12c)(13 + 12c)

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4- Find the square : (9 - b)²
(9 - b)²

Expand exponent
= (9 - b)(9 - b)

Distribute
= 9(9 - b) - b(9 - b)

Distribute again
= 81 - 9b - 9b + b²

Simplify
= 81 - 18b + b²

Rewriting into standard form, (descending powers)
= b² - 18b + 81

Therefore, the answer is A.
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Answer 4

PLEASE READ THIS I SPENT LOT OF TIME THINKING & TYPIN THIS
1st question u just have to multiply
2nd question &third question they r a bit difficult
if u have to factorize a polynomial whose terms r a no. , a variable and a variable &no. both then u put mixed variable first variable 2nd and no. third then divide the 2nd term such that when u add it u get that no itself and its product is equal to the product of the other two terms then u can factorize it easily
for eg i take ur own sum
2x^2-5x-18
2x^2-9x+4x-18
x(2x-9)+2(2x-9)
(x+2)(2x-9)
ur sum is solved

third sum is a^2-b^2

fourth sum u just sqr it
itll be
C) b^2+81-9b

if u need any help then
[e-mail]

Answer 5

1. 4x² + 29x - 24

2. (2x-9) (x+2)

4. b² - 18b + 81

Answer 6

Hi. I know algebra seems hard but you'll have a much better time in life if you make the effort to learn any subject, even if you don't think you'll need it in life. Hint: a negative times a negative is a positive. Always. Take a good look at D.

Answer 7

10 Points? It must be woth 100 to answer that problem.

Answer 8

http://www.doyourowngoddamnhomework.com

Answer 9

is this ur homework?