y= x^2 - 9x +20
2006-08-25 08:16:38 · 5 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
y = x² - 9x +20
y = (x - 5)(x - 4)
=> x = 5 and x = 4
2006-08-25 08:32:00 · answer #1 · answered by Brenmore 5 · 0⤊ 0⤋
x=5 n x=4
2006-08-28 20:14:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x-intercepts are points of the form (a,0)
This means set y = 0 and solve for "x"
y = 0 = x^2 - 9x + 20
x^2 - 9x + 20 = 0
(x )( x ) = 0
(x 4)( x 5) = 0
(x - 4)( x - 5) = 0
x = 4 or x = 5
x-intercepts are (4,0) and (5,0)
2006-08-25 16:24:14 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y = x^2 - 9x + 20
x^2 - 9x + 20 = 0
(x - 5)(x - 4) = 0
x = 4 or 5
2006-08-25 16:30:40 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
The x intercept is where y=0. (That's where it crosses the x axis)
So you need to solve
0=x^2-9x+20
Now go forth and factor the quadratic equation (you didn't think I was going to do your homework for you, did you?)
2006-08-25 08:24:10 · answer #5 · answered by PrincipalNZF 2 · 0⤊ 0⤋