How do I factor 7x3-4x2+8x?

1 ⤊

2006-08-25 08:01:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

7x3-4x2+8x
just from one ( x ) you can factor.

x[ (7x^2) -(4x) + 8) =0 =>

x=0
OR
(7x^2) -(4x) + 8)=0

2006-08-25 10:04:54 · answer #1 · answered by sweetie 5 · 1⤊ 0⤋

7x^3 - 4x^2 + 8x = x(7x^2 - 4x + 8)

this can't be factored any further.

2006-08-25 15:26:30 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋

x(7x^2-4x+8)=0
That's about as factored as I can make it.

2006-08-25 15:10:34 · answer #3 · answered by jfahd 4 · 0⤊ 1⤋

Previous answe r is right. You can't factor beyond that...

2006-08-25 15:15:55 · answer #4 · answered by Epicarus 3 · 0⤊ 1⤋