it is from the lesson permutation and combination
2006-08-25 05:15:43 · 4 answers · asked by jefri t 1 in Science & Mathematics ➔ Mathematics
They are all 4 digit numbers.
Number of numbers = 4 x 3 x 2 x 1 =24.
Each digit occurs 6 times in each position.
The sum of the numbers in each position = (2 + 3 + 4 + 5) x 6 = 84
The sum of all the numbers = 84000 + 8400 + 840 + 84 = 93324
2006-08-25 05:30:28 · answer #1 · answered by baskaran r 2 · 0⤊ 0⤋
I'm going for 93,324
- There are 24 combinations of those numbers (4!)
- Each number should be represented equally in the combinations.
- The average of all the numbers is 3.5
So the sum of the ones digits should be 3.5*24 or 84 -> the last number is 4.
The sum of the tens digit is 84 plus a carry of 8 = 92 so the tens digiti is 2.
The sum of the hundreds digit is 84 + a carry of 9 = 93 so the hundreds digit is 3
The sum of the thousands digit is 84 + a carry of 9 = 93 thousands.
2006-08-25 05:18:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
We start off with 24 numbers so each column when you add has six 2's, six 3's, six 4's and six 5's. So each column adds up to 84 so the final answer is 93,324
2006-08-25 05:29:55 · answer #3 · answered by MollyMAM 6 · 0⤊ 0⤋
2345
2354
2534
2543
2435
2453
3452
3425
3524
3542
3254
3245
4235
4253
4352
4325
4523
4532
5324
5342
5432
5423
5234
+5243
______
93,324
2006-08-25 05:42:51 · answer #4 · answered by LADY ICE 3 · 1⤊ 0⤋