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2NO + O2 ---> 2NO2

In on experiment 0.886 moles of NO is mixed with .503 mole of )2. Calculate which of the two reactacts is the limiting reagent. Calculate also the number of moles of NO2 produced.

PLEASE HELP ME. I'M TERRIBLY CONFUSED AND LOST.

2006-08-25 04:55:19 · 6 answers · asked by dingdong 1 in Science & Mathematics Chemistry

6 answers

First Question:

1) First thing, make sure the equation is correct and balanced:
-I assume it is correct, and if it is, it is balanced as written

2) Determine the relative proportions (the "ratio") of moles of the reactants:

-You have a ratio of 2 moles NO for every 1 mole of O2, thus a 2 to 1 ratio, usually written as 2:1. This means you need two moles of NO for every mole of O2 that used.

3) Since they give the moles in the question, no conversion is necessary. you have 0.886 moles of NO and 0.503 moles of 02.
To react both reactants completely, you would need twice as many moles of NO as you would of 02 moles. But you do not have twice the number of moles of NO. (2 X 0.503 = 1.006; that is the number of moles of NO you would need for this reaction to react completely).
Therefore, the limiting reactant is NO.

Question Two:

In this question, you must first determine how many moles of product (N02) will be produced, using the mole ratio of 2NO gives 2N02. This ratio is 2:2, which you can reduce to 1:1. You pick the NO reactant, because that is the limiting reagent.

1) According to the 1:1 ratio, you will produce 0.886 mole of the product N02.

2) Now convert 0.0886 mole of N02 back into grams:

moles = grams / molecular weight

so: grams = moles X molecular weight

fill in the numbers:

grams N02 = 0.886 mole N02 X 46 g/mol N02

= 40.8 grams of N02

use only 3 significant figures in your answer, as both of your moles in question have 3 significant figures.

Note: I am using the atomic weights of N = 14 and 0 = 16. My answer may differ slightly from others if different atomic weights are used.

And that's how you do it!

2006-08-25 05:22:55 · answer #1 · answered by MrZ 6 · 2 1

ok, so you know you need 2 moles of NO and 1 mole of O2 to produce 2 moles of NO2.

2NO: 2NO2 is a ratio of 1:1, thus 0.886 moles of NO is needed to produce NO2

O2: 2NO2
you need 1 mole of oxygen to produce 2 moles of NO2
ratio is 1:2
you have 0.503 moles O2, thus in order to complete the reaction you would need 1.006 moles O2, which you don't have thus O2 is the limiting reagent and the whole reaction is based on this information. I think since it's a 1:1 ratio the amount produced is .503 moles NO2

2006-08-25 05:07:11 · answer #2 · answered by Natasha B 4 · 0 0

Well, because I don't do homework, I'll just try and clear this up for you. This question is easy to apply to real world examples. Think of it like pizza and people. You need to find out how many people, how much pizza and how much each person will eat to know how much you need and what you'll be short of.
The first thing you need to do is find the number of moles. That's the number of molecules so it'll tell you how many things you need to hook up. So it's the number of people and the number of pizza slices. You find the number of moles by dividing the number of g/mole you have by the number of g given. Like finding the number of pizza slices by dividing the weight of all of the pizza by the weight/slice.
So then, you figure out how much of each thing you need to get the end result. Like how much pizza per person. In this case you need 2 NO molecules for one 02. So to find how much NO you need to react completely with the O2 you have multiply the number of O2 moles by 2. If that number is more than the moles of NO you have then you'll need more NO to react completely with the O2 and the NO is the limiting reagent. If it's not then the O2 is the limiting reagent.
See? So if you need 2 pieces of pizza/person then you would multiply the number of pizza slices by 2 and compare it to the number of pizza.
I hope that helped.

2006-08-25 05:10:23 · answer #3 · answered by TheHza 4 · 0 0

Find the molar ration of NO to O2 in the reaction.

2 NO + O2 --> 2 NO2
In this reaction, the mole ratio is 2 moles of NO to 1 mole of O2, meaning you need twice as many moles of NO as you do O2.

It is stated that you have .886 moles of NO and .503 moles of O2.
We already know you need twice as many moles of NO as O2....do you?
No, you have excess O2, this means that NO is your limiting reagent and NO determines the number of moles of NO2 produced.

What is the mole ration between the number of moles of NO reacted and number of moles of NO2 produced?
2 moles NO : 2 moles NO2
or 1 to 1.

So if NO is you limiting reactant and the mole ratio is 1 : 1 between moles of NO and NO2, you will produce the same number of moles of NO2 after the reaction is complete as you originally had moles of NO.

Therefore, in the end, .886 moles of NO2 will be produced, leaving .06 moles of O2 gas unreacted.

2006-08-25 05:03:39 · answer #4 · answered by mrjeffy321 7 · 0 0

next time, listen in class and ask questions as soon as you have them, not after you get home.

2006-08-25 04:58:57 · answer #5 · answered by Anonymous · 1 0

It must be back to school time .............so many people aparantly need help with homework

2006-08-25 05:01:08 · answer #6 · answered by xox_bass_player_xox 6 · 1 0

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