give me a answer if you are genies?

Question

A large water tank has two inlet pipes (a large one and a small one) and one outlet pipe. It takes 3 hours to fill the tank with the large inlet pipe. On the other hand, it takes 5 hours to fill the tank with the small inlet pipe. The outlet pipe allows the full tank to be emptied in 8 hours.

What fraction of the tank (initially empty) will be filled in 1.22 hours if all three pipes are in operation? Give your answer to two decimal places (e.g., 0.25, 0.5, or 0.75).

Answer 1

YOUR RIGHT ANSWER IS 0.50

Answer 2

Here is how you solve this. You assume the tank has a volume of anything you want. I'll use 1. The big inlet pipe flows 1/3 per hour. The small one flows 1/5 per hour and the outlet flows 1/8 per hour out. If all three are flowing then the flow rate is

1/3 + 1/5 - 1/8 per hour.

Multiply that by 1.22 hours and that is how full the tank will be.

Answer 3

Three Pipes

1). Large Pipe fill tank in 1/3 hours

2). Small Pipe fills tank in 1/8 hours

3). Outlet Pipe fills Tank in 1/5 Hours

4) wilth all three pipes in operation it will fill the tank in 1.22 hours

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Solving for all three pipes operating at once

1). 1/3 x 1.22 = 0.40666667

2). 1/5 x 1.22 = 0.244

3). 1/8 x 1.22 = 0.1525

Caculating the sum of all three pipes

0.40666667 + 0.244 = 0.65066667 - 0.1525 = 0.49816667

The answer is .50 rounded up to two decimal places

Answer 4

I'm no genie, but I can give this a shot...

Inlet 1 = 3 hours / 1 tank
Inlet 2 = 5 hours / 1 tank
Outlet = 8 hours / 1 tank

Contributions:

Inlet 1: 1.22 hours / [3 hours / 1 tank] = .407 tank
Inlet 2: 1.22 hours / [5 hours / 1 tank] = .244 tank
Outlet: 1.22 hours / [8 hours / 1 tank] = .153 tank

Add the contributions from each pipe:

=[.407] (tank) + [.244] (tank) - [.153] (tank)
=[.50] (tank)

half a tank

Answer 5

the fraction of the tank filled in one hour when all the three tanks are open will be given by (1/3)+(1/5)-(1/8)
taking LCD this will be equal to (40+24-15)/120=49/120
so in 1.22 hrs the fraction will be 1.22(49/120)=0.5 approx.

Answer 6

Large inlet pipe will let in (1/3)(1.22)=.4067 of tank.
Small inlet pipe will let in (1/5)(1.22)=.2440 of tank.
Total of both inlets is .6507 of tank
Outlet pipe will drain (1/8)(1.22)=.1525 of tank.
.6507-.1525=.4982 of tank, or .50 of tank, rounded to 2 places

Answer 7

Lp - Large pipe,
Sp - Small pipe
Op - Outlet pipe.
hr - hour
1T - One full tank

For Lp :
3hr = 1T
1hr = 1/3 T
1∙22hr = 1/3 * 1∙22T
1∙22hr = 0∙406666....T

For Sp :
5hr = 1T
1hr = 1/5 T
1∙22hr = 1/5 * 1∙22T
1∙22hr = 0∙244T

For Op :
8hr = 1T
1hr = -1/8 T (Outward flow so have a minus sign).
1∙22hr = -1/8 * 1∙22T
1∙22hr = -0∙1525T

When three pipes are in operation together:
1∙22hr = (1∙22hr x Lp) + (1.22hr x Sp) - (1∙22hr x Op)
1∙22hr = 0∙406666.... + 0∙244 - 0∙1525
1∙22hr = 0∙49816666
1∙22hr ≈ 0∙50
As a fraction:
[0∙50 x 10] /10 = 5/10 = ½T

Answer 8

Let
x = fraction of the tank filled after 1.22 hrs

x = 1.22 hr/3 hr + 1.22 hr/5 hr - 1.22 hr/8 hr
x = 0.40666.... + 0.244 - 0.1525
x = 0.4981666666666666...
x ≈ 0.50

^_^

Answer 9

tank is 1 .
pipes are x ,y ,z
1 = 3x=5y=8z ->
x=1\3 , y = 1\5 , z=1\8
(x+y-z)*1,22 = answer

Answer 10

Better off getting a new tank I reckon.1 inlet/1 outlet is all you're ever going to need.LOL!!!.

Answer 11

Genies are mythological creatures and do not really exist.