What will be the volume of a gas sample at 309 K if its volume at 215 K is 3.42 L? Assume the pressure is cons

Answer 1

gtn has the right idea, but substituted incorrectly:

V1/T1 = V2/T2 , thus

V2 = V1T2/T1 = (3.42 liters)(309K)/(215K) = 4.92 liters

If pressure remains constant, when you increase the temperature (from 215K to 309K), the volume must also increase.

Answer 2

if PV=nRT,

and P, n and R are contants, you get:

V1/T1 = V2/T2
V2 = (V1*T2)/(T1) = 3.42*215/309 = 2.38 L