2006-08-25 04:21:40 · 38 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i.
i is a special number that does not exist in the standard number line (such numbers are called 'imaginary'). You can think of it as being the same distance away from 0 as 1 is, only at a 90 degrees angle away from the line between 0 and 1.
2006-08-25 04:24:10 · answer #1 · answered by Anonymous · 4⤊ 0⤋
1
2006-08-25 04:49:02 · answer #2 · answered by Yahoo! 5 · 0⤊ 1⤋
1
2006-08-25 04:27:13 · answer #3 · answered by Anonymous · 0⤊ 4⤋
1
2006-08-25 04:26:55 · answer #4 · answered by icac83 3 · 0⤊ 4⤋
It's "i". "i" is defined in such a way that i squared is equal to -1. This may seem absurd but it is very helpful theory in maths.
The square of any positive or negative number is positive, and the square of 0 is 0. Therefore, no negative number can have a real square root. However, it is possible to work in a larger number system, called the complex numbers, in which negative numbers have square roots. This is done by introducing a new number, called the imaginary unit, which is defined to be a square root of -1. This number is usually denoted by i (sometimes j ).
2006-08-27 17:35:39 · answer #5 · answered by Subakthi D 2 · 0⤊ 0⤋
1
2006-08-25 04:24:15 · answer #6 · answered by Rudebox77 4 · 0⤊ 5⤋
the square root of -1 is i which is by defenition one of the 2 solutions to the equation x^2 = -1, the other solution being -i. Similarly, the square root of -9 is 3i, and so on.
2006-08-25 04:43:19 · answer #7 · answered by Vendetta 2 · 0⤊ 0⤋
IT'S Square Root(-1) is = i
2006-08-25 04:51:18 · answer #8 · answered by Anonymous · 0⤊ 0⤋
there is no square root of -1
2006-08-25 06:48:48 · answer #9 · answered by christopkim951 1 · 0⤊ 0⤋
The square root of -1 is i, which stands for imaginary.
2006-08-25 04:30:21 · answer #10 · answered by Lonnie P 7 · 2⤊ 0⤋
the square root of -1 is i.
2006-08-25 04:27:41 · answer #11 · answered by bostonguy235 2 · 3⤊ 0⤋