What's the integral of a constant ?

Answer 1

(The constant) * (what you're integrating with respect of)

So if you're integrating 5 with respect to x, the answer is 5x. +C, of course.

Answer 2

if the integral is of a non-zero constant, c, then it is cx + d, where d is some other constant. if the integral is of 0, then the answer is some real constant, which could again be 0.

Answer 3

constant times the variable with respect to which it is integrated
so integral of 5 dx=5x+C
integral 23 dy=23y+C
and so on

Answer 4

(The constant) * (what you're integrating with respect of)

Answer 5

If the constant is C, then the integral is Cx + D, where D is any other constant.

Answer 6

Let a = be any constant
then
∫(a)dx = ax + C
where C is the constant of integration (or simply, any constant, which CAN also be equal to a)

E.g.

∫(-2)dx = -2x + C
∫(-1)dx = -x + C
∫(0)dx = C
∫(1)dx = x + C
∫(2)dx = 2x + C

Answer 7

I've attached a beautifully formatted and carefully annotated PDF. It looks like textbook notation, so it's easy to read.
http://www.tomsmath.com/step-by-step-example-of-finding-the-antiderivative-of-a-constant.html

Answer 8

Good Morning ☻

I have a question...

assuming in the last expression..

=> (integrating)1/xdx = (integrating)1/ydy
=> ln|x| = ln|y|+C
=> (next step)
=>ln|x| = ln|y| + ln C
(here is my question.. Can anyone can explain me why ln c are put in the constant of integration? )

Answer 9

it is that constant plus c
e.g
{1} = x+c. what is the intergral of 1+c?

Answer 10

That property is called Linearity. Answer is True.