I wish I did not have to take this class. It is too hard for me.
2006-08-25 03:49:20 · 4 answers · asked by emdorsheimer 1 in Education & Reference ➔ Homework Help
See my other answers for details on how to do this.
Hint: For this one, first take out the common pieces
That means, first take out the 2 and take out the a,
or, take out 2a, which will leave you something much more familiar and doable! Very doable, especially if you saw my other answers.
2006-08-28 05:44:48 · answer #1 · answered by Yada Yada Yada 7 · 1⤊ 0⤋
it's not too bad.. don't give up. just make sure u can group similar #'s together....
2a^3 + 52a^2b + 96ab^2
take out a 2 and an a, because all of them have that in common:
2a(a^2 + 26ab +48b^2)
2a [(a+24b)(a+2b)]
2006-08-25 05:06:12 · answer #2 · answered by sasmallworld 6 · 0⤊ 0⤋
2a^3+52a^2b+96ab^2
Notice that in 3 terms there is 2a, so we can put it outside as common factor so we got:
2a(a^2+26ab+48b^2)
Now, we should factor (a^2+26ab+48b^2) into (a+24b)(a+2b)
So, we got:
2a(a+24b)(a+2b)
2006-08-25 04:00:59 · answer #3 · answered by Neo_Apocalypse 3 · 0⤊ 0⤋
I think it's 2a(a+24b)(a+2b).
2006-08-25 03:53:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋