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2006-08-25 00:23:17 · 3 answers · asked by please answer this 1 in Science & Mathematics Physics

3 answers

People above have provided some valid insight. If you are looking for ‘how much’ then the answer needs to be quantified.

Buoyant Force =
=Weight of the liquid displaced=
=(Mass of Liquid displaced) x (Gravitational Acceleration)

F=W=mg

Where
Mass of the liquid displaced =
=(Volume of the liquid displaced) x (density of the liquid displaced)

For example if you placed an object in the water and it displaced 1000cm cubed, then you have displaced 1000g or 1kg of water. The weight of water is equal to the buoyant force water exerts on this object;

Fb=W(H20)=mg= 1kg (9.8m/s^2)=9.8N

The net force on the object that weighs Wo is;

Ft=Fb – Wo

I do not know how much the object weighs, you can figure this out :)

I hope it helped.

2006-08-25 03:01:38 · answer #1 · answered by Edward 7 · 0 0

well, the "greatness" of the bouyant force only depends on the mass of the liquid displaced by the body. hence it is obvious that when the body is not completely immersed, the force is lesser than when it is completley submerged.
the bouyant force also depends on the density of the liquid.

2006-08-25 09:43:50 · answer #2 · answered by pranav 2 · 0 0

It's the mass of the water (or whatever the fluid is) displaced by the body minus the mass of the body itself


Doug

2006-08-25 07:29:59 · answer #3 · answered by doug_donaghue 7 · 0 0

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