Anybody who can solve this one?

Question

2.While traveling from one station to the next, after 1 hour a piston burst. As a result the party could only proceed at 3/5 their original speed and arrived 1 hour late. If however the accident had
happened 50 minutes later, they would have arrived 40 minutes earlier than the time they did arrive
at. What is the distance between the stations?

Answer 1

this is simple but your missing one key piece of info the original speed so lets just say they where going 75mph that breaks down to 1.25 miles per min the 3/5 original speed is irrelivant. it says they where going for 1 hour at original speed so thats 75 miles the second part say if the accident happened 50 min later, that would put them at 1hr 50 min going 75mph or 110min going 1.25miles per min which equals 137.5 miles between stations.

of course this is goin 75mph I dont know the true speed.

Answer 2

Cannot be solved.

The first statement implies that the traveling time is 150 minutes, but does not give the distance.

t v = 60 v + 0.6 v t
t = 60 + 0.6 t
0.4 t = 60
t = 150 minutes

The second statement implies that the traveling time is 140 minutes:

t v = 110 v + 0.6 v (t - 90)
t = 110 + 0.6 t - 54
0.4 t = 56
t = 140

Therefore the information is contradictory.

Answer 3

it could be the gas PUMP, it quite is a little harder to adjust because it really is in the gas tank. (In different words, it made experience to attempt replacing the filter out first.) It sounds like the engine is compensating for the failing pump through sucking the gas in .... a minimum of till your RPMs bypass down and the pump has to do more desirable of the artwork. you're able to get the pump examined for a real looking diagnostic fee rather of utilising trial and mistake to discover the problem. you don't desire to adjust the gas pump except you ought to, noticeably on a automobile with a low clearance. at the same time as the section isn't that extreme priced, the exertions might want to be fairly undesirable. That pump is going to be perplexing to get admission to and also you've were given to drop the gas tank to modify it.

Answer 4

let s (per minute) be the speed of train and d be the distance and t (in minutes) be the original time required to travel

d = st
d = s(60) + 0.6s(t-60+60) = s(60+0.6t)
d = s(110) + 0.6s(t-110+20) = s(110 +0.6t - 54) = s(56+06t)

numbers do not add up: 60+0.6t = 56+06t = t ?

Answer 5

say the distance is x km
the train speed is ykm/hr

so from the first condition we have

1+ (x-y)/3y/5 = T1

T1 - x/y = 1

or 1+(x-y)/(3y/5) -x/y = 1
or 5(x-y)/3y-x/y=0
or 5x-5y-3x=0
or 2x-5y=0
or x = 5/2y

now from the second condition we have

1+5y/6 + (x-11y/6)/(3y/5) = T2

Now T1-T2 = 2/6 hrs

or 1+5(x-y)/3y - 11y/6 - 5(6x-11y)/18y = 1/3
or 1+5(5x-5.2x/5)/3.2x-11.2x/5.6 - 5/18.2x(30x-22x) = 1/3
or 1+5/2-20/18-1/3=22x/30
or x=2.80km

Answer 6

ok, i am not a brainiack, so dont trust my word 100%. check it yourself.

A------- 60mins break-----------------late60mins--B

A-------110mins-----------------40 mins earlier, late 20 mins--B

at first i thought
A.120 min
B. 150 mins
C. 3/5 of 110mins = 3/22= 7.33mins
D. 110+7.33+20= 137.33 minutes between the stations
i think 137.33 is the answer

Answer 7

first off, we'd need the speed they were traveling in order to solve this. and like everyone else said, do ya homework yaself

Answer 8

is there sompin missin from this question like the orginal speed of train b4 piston burst?

Answer 9

Numbers dont add up.. seems the question is wrong or missing something...

Answer 10

Oh, how i hate this kind of travelling questions