A tortoise crawling at a rate of 0.1 mph passes a resting hare. The hare wants to rest another 30 minutes before chasing the tortoise at the rate of 5 mph. How many feet must the hare run to catch the tortoise. Steps included please?
2006-08-24 18:04:43 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
When the hare catches the tortoise the tortoise will have been moving 1/2 hour longer than the hare. The tortoise moves at 0.1 mph, or 528 ft/hr. So in 30 minutes the tortoise will have moved 264 feet.
At that instant the hare will wake up and begin chasing. The hare will catch the tortoise in x hours.
264 + 528x = distance traveled by tortoise before caught by hare
26400x = distance traveled by hare before catching tortoise
When 264 + 528x = 26400x, the two animals are even.
264 = 25872x
0.0102 = x
The hare will catch the tortoise in less than a minute - in fact, in 36.73 seconds the race will be over. In that time, the hare will travel 26400*0.0102 = 269.39 feet.
2006-08-24 18:41:28 · answer #1 · answered by jimbob 6 · 1⤊ 0⤋
0.1 miles is = to 527.969102 feet.. so the tortoise travels at around 527.97 feet per hr.. divide it by 2 (because half of an hr is 30 mins..) so u will get 264... thats the distance of the turtle from the resting hare. if the hare will gonna catch em up w/ the speed of 5 miles per hr, he can probably catch him within 6 mins.. and tahts 264 feet... confusing? LOL..
2006-08-24 18:22:59 · answer #2 · answered by Peng 1 · 0⤊ 1⤋
5 feet
2006-08-24 18:10:36 · answer #3 · answered by Thomas Odin M 2 · 0⤊ 0⤋
IDK. I think the hare should have ran and then rested and then there wouldn't be a question! I never liked these problems as a kid. And I taught school!!!
2006-08-24 18:12:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋