1.Solve the equation 3m^2+6m=3 using the quadratic formula.
2.If the garden box has dimensions x by x feet and an area in square feet equal to the perimeter in feet, what is the value for x that satisfies the requirements? (Hint: The box is a square.)
3.To graphically solve the quadratic equation x^2+3x-10=5 what do u do.
2006-08-24 17:35:29 · 8 answers · asked by wipp 1 in Education & Reference ➔ Homework Help
uhhhhhh....
math...yeah...i dont do math
2006-08-24 17:38:36 · answer #1 · answered by once_upon_a_dream 2 · 0⤊ 0⤋
2. X=4
2006-08-25 00:42:56 · answer #2 · answered by Bethany 7 · 0⤊ 0⤋
1. 1 + square root of 2; 1 - square root of 2
2. x = 4; 4^2 = 16 and 4(4) = 16
3. The graph on quad. eq is the parabola, in which the points where the parabola intersects the x - axis are called roots or solutions.Use the discriminant- b^2 - 4ac, this tells you how many roots the equation has. Positive# - 2 roots. Zero - 1 root. Neg.# - 0 root.
Hope this helped
2006-08-25 00:54:48 · answer #3 · answered by that's funny 3 · 0⤊ 0⤋
The answer to 2 is 2. The others are not that difficult, but not so easy to show here where symbols can't be used.
3. Draw a graph!!
2006-08-25 00:42:42 · answer #4 · answered by Nelson_DeVon 7 · 0⤊ 0⤋
the asnwer to 2 is 4
2006-08-25 00:42:13 · answer #5 · answered by manza 2 · 0⤊ 0⤋
for number one. i have 2 answers the first answer is m=5 the second is m= 1over 3 as in fraction form.
2006-08-25 00:44:17 · answer #6 · answered by hopar 2 · 0⤊ 0⤋
1. m = [-b +- sqrt(b^2 - 4*a*c)] / (2*a)
a = 3, b = 6, c = -3
m = [-6 +- sqrt(6^2 - 4*3*-3)] / (2*3)
= [-6 +- sqrt(36 + 36)] / 6
= [-6 +- sqrt(72)]/6
= [-6 +- sqrt(36 * 2)]/5
= [-6 +- 6*sqrt(2)]/6
= -1 +- sqrt(2)
2006-08-25 00:47:27 · answer #7 · answered by bogusman82 5 · 0⤊ 0⤋
try looking it up at your homework hotline cause I'm in dumb math
2006-08-25 00:40:53 · answer #8 · answered by Smiley 24/7 1 · 0⤊ 0⤋