can anyone help me sove this step by step. sqaure root of x plus y divided by square root of x minus y
2006-08-24 17:21:16 · 8 answers · asked by Sams 2 in Science & Mathematics ➔ Mathematics
sqx+y
sqx-y
(sqx+y)(sqx-y)
sqx-y
x + sqxy - sqxy - y^2 = 0
x - y^2 = 0
x = y^2
y = sqx
that may be right...
2006-08-24 17:30:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It cannot be "solved" because there are no numbers, but the answer should look like... root sign with x + y inside of it then divided OVER root sign with x - y inside of it
It's difficult to show that on here when u can't "write" it. :)
2006-08-24 17:26:58 · answer #2 · answered by scrawndogg25 3 · 0⤊ 0⤋
I could help you remove the root sign.Just Square the whole thing
root of(x+y)/root of (x-y)
you'll get x+y/x-y
Now if you can use the values for x substitue it and solve it.
I think the above is correct.
2006-08-24 17:29:54 · answer #3 · answered by vintalite 2 · 0⤊ 1⤋
(sqX+y) / (sqX-y)
find y
sqX-y
=> sqX =y
X = ysq
sub (sq(ysq) + y) / sq(ysq - y)
cancel sq
(y + y) / (y - y)
=2y / 0
=e
the answere for both equations is an error
2006-08-24 17:56:50 · answer #4 · answered by stupidgirl 2 · 0⤊ 0⤋
What help do you need, there is nothing to do here.
2006-08-24 17:28:38 · answer #5 · answered by Nelson_DeVon 7 · 0⤊ 0⤋
nope: dont know sori
2006-08-24 17:27:16 · answer #6 · answered by bubba-22 1 · 0⤊ 0⤋
sorry.........I wish Icould..........but i'm as bad as you though. Maybe there will be a math whiz on here. Thanks for the points though.
2006-08-24 17:27:06 · answer #7 · answered by TX girl 2 · 0⤊ 0⤋
AND EQUAL TO WHAT? VERY UNCLEAR!
2006-08-24 17:31:11 · answer #8 · answered by David F 2 · 0⤊ 0⤋