and football occupies 30 percent of the students involved in sports...whats the overall (100%) amount of students involved in sports...
i just want to see if I was the only one who couldn't get this at first..i felt so stupid.....do you know the answer...first one to get it right gets ten points...
2006-08-24 13:26:05 · 4 answers · asked by mixed 1 in Science & Mathematics ➔ Mathematics
these people are right but the way they set up their problem is not the most intuitive
the problem says that 53 students is 30% of the total involved in sports
so 53=30% of x
of always means multiply so
53=.3*x
x=53/.3
x=177
2006-08-24 14:11:45 · answer #1 · answered by zmonte 3 · 0⤊ 0⤋
the wording is confusing, the overall percentage of people involved in sports is 100% since every one involved in sports is in fact involved in sports (redundant indeed). However, if the point is to discover the overall amount of students in sports in proportion to the total student population, then we cannot determine the answer because we have no clue as to how many students there are total who are NOT involved in sports. Otherwise my answer would have to be 100%.
2006-08-24 14:18:22 · answer #2 · answered by fmg134s 2 · 0⤊ 0⤋
I'm thinking it's 10/3 * 53. or 530/3. or 176.67? Of course there are no fractional people, however. So the 30 percent must not be quite exact.
2006-08-24 13:30:00 · answer #3 · answered by Halbert 2 · 0⤊ 0⤋
football=53 football equals=30% 30%=53 1%=1.76666666
100%=176.6666 which rounds to 177
2006-08-24 13:35:44 · answer #4 · answered by cccbonick 2 · 0⤊ 0⤋