what can you determine about the graph of y=mx+b when x=0
what can you determine about the graph of y=mx+b when y=0
the points (-2,4), (0,2),and (3,a-1) are on one line. find a
2006-08-24 13:16:25 · 4 answers · asked by mycutemy 2 in Education & Reference ➔ Homework Help
when x=0, it cuts the y-axis at (0,b)
when y=0, it cuts the x-axis at (-b/m,0)
the gradient of (-2,4) and (0,2) is 4-2/-2 = -1
so the equation of the line joining them is y-4 = -1(x+2)
y-4 = -x - 2
x + y = 2
Now (3, a-1) lies on this line, so substitute the points:
3 + a - 1 = 2
a = 0
2006-08-24 13:21:51 · answer #1 · answered by K.P. 3 · 0⤊ 0⤋
skilled at deceiving others
2006-08-24 21:41:56 · answer #2 · answered by jose m 1 · 0⤊ 0⤋
i dont know what this is!
2006-08-24 21:37:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Find a .....what ?
2006-08-24 20:22:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋