(5x^-3/4x^3) ^-2
2006-08-24 12:16:09 · 6 answers · asked by your_ma_was_here 1 in Science & Mathematics ➔ Mathematics
16x^12/25
DutchProf was so close!
2006-08-24 12:37:36 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
Replace negative exponents by fractions:
The expression in parentheses is equal to
[5/(x^3)]/[4x^3] = (5/4) / (x^3 * x^3) = (5/4)/x^6
The -2nd power is
[(5/4)/x^6]^(-2) = {1/[(5/4)/x^6]}^2 = {x^6/(5/4)}^2
= x^12 / (25/16) = 25 x^12 / 16
2006-08-24 19:24:22 · answer #2 · answered by dutch_prof 4 · 0⤊ 1⤋
if by this you mean
((5x^-3)/(4x^3))^-2
((4x^3)/(5x^-3))^2
(4/5)^2 * ((x^3)/(x^-3))^2
(16/25) * (x^(3 - (-3)))^2
(16/25) * (x^(3 + 3))^2
(16/25) * (x^6)^2
(16/25) * x^(6 * 2)
(16/25)x^12
ANS : (16/25)x^12 or (16x^12)/25
2006-08-24 20:10:11 · answer #3 · answered by Sherman81 6 · 1⤊ 0⤋
x^4=17/4
2006-08-24 20:21:58 · answer #4 · answered by rx.vinay.ph 2 · 0⤊ 1⤋
why don't you simplify it and i'll tell you if you're right!
2006-08-24 19:21:41 · answer #5 · answered by jack b 3 · 0⤊ 1⤋
[(5x˳)/4x³]˲
[(1/5x³)/4x³/1]˲
[(1/5x³)*(1/4x³)]˲
(1/5x³*4x³)˲
(1/20x^6)˲
(20x^6)²
400x^12
or
[(5x˳)/4x³]˲
(5x˳)*(4x˳)]˲
(20x^-6)˲
400x^12
2006-08-25 14:52:21 · answer #6 · answered by angels_carolzinha 6 · 0⤊ 1⤋