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2006-08-24 11:37:17 · 15 answers · asked by AT 2 in Science & Mathematics ➔ Mathematics
(5m+2n)^2=25m^2+kmn+4n^2
25m^2+10mn+10mn+4n^2
25m^2+20mn+4n^2=25m^2+kmn+4n^2
-25m^2
20mn+4n^2=kmn+4n^2
-4n^2
20mn=kmn
divide mn/mn
20=K
20
2006-08-24 11:41:41 · answer #1 · answered by Transformers20 2 · 0⤊ 0⤋
k=1
2006-08-24 11:43:40 · answer #2 · answered by Anonymous · 0⤊ 1⤋
(5m + 2n)^2 = 25m^2 + kmn + 4n^2
(5m + 2n)(5m + 2n) = 25m^2 + 10mn + 10mn + 4n^2
25m^2 + 20mn + 4n^2
k = 20
2006-08-24 13:12:58 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
(5m+2n)^2
=(5m+2n)*(5m+2n)
=5m(5m+2n)+2n(5m+2n)
=25m^2+10mn+10mn+4n^2
=25m^2 + 20mn +4n^2,
comparing this with 25m^2 + kmn +4n^2,
we get k=20.
2006-08-25 01:54:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
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2016-12-11 14:49:07 · answer #5 · answered by ? 4 · 0⤊ 0⤋
You multiply 5 by 2 then double it so.....k=20
2006-08-24 11:39:54 · answer #6 · answered by MollyMAM 6 · 0⤊ 0⤋
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2006-08-24 11:43:00 · answer #7 · answered by afterflakes 4 · 0⤊ 2⤋
k = 20 , but you should do it by yourself...
2006-08-24 11:42:16 · answer #8 · answered by will_rj 2 · 0⤊ 0⤋
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2006-08-24 11:38:22 · answer #9 · answered by EMAILSKIP 6 · 0⤊ 2⤋
5m(2)
2006-08-24 11:38:28 · answer #10 · answered by ????a?? ? 5 · 0⤊ 2⤋