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# The property demonstrated in the following equation is
(10 × x) + y = y + (10 × x)

associative property of addition
commutative property of addition
commutative property of multiplication
Neither side of the equation is equal to the other.


# The property demonstrated in the following equation is
(2x – 4y)3 + 5z = 6x – 4y + 5z

substitution property of equality
distributive property
reflexive property of equality
Neither side of the equation is equal to the other.


# The property demonstrated in the following equation is
5 + (8x × y)2z = 5 + 8x(y × 2z)

associative property of multiplication
commutative property of multiplication
distributive property
Neither side of the equation is equal to the other.

To maintain a 92% average, what score does Kari need on her next algebra test if her test scores have been 89, 96, 90, and 85 thus far?

92
95
98
100

2006-08-24 11:18:55 · 5 answers · asked by doomooman168 2 in Science & Mathematics Mathematics

Don't worry, this isn't my homework...Besides, I'm in pre-calculus as a sophmore in highschool. Oh, and school starts on the 8th of Sept.

2006-08-24 11:38:33 · update #1

5 answers

1. commutative prop. of addition
2. distributive prop.
3. associative prop. of mult.
4. 100

I think that answers all of them.

2006-08-24 11:27:06 · answer #1 · answered by Scottie0210 2 · 0 0

Wow, somebody's not paying attention. On problem b, the answer is neither side of the equation is equal to the other. 3(2x-4y)=6x-12y, not 6x-4y

The answers given by the others to the other problems are correct.

2006-08-25 00:26:46 · answer #2 · answered by Pascal 7 · 0 0

The answers should be (in order):

commutative property of addition
distributive property
associative property of multiplication
100

I sure hope this isn't your homework....

2006-08-24 18:31:43 · answer #3 · answered by Kelvin L 2 · 0 0

Scottie's got them all right - no need to duplicate his right answers

2006-08-24 18:30:57 · answer #4 · answered by MollyMAM 6 · 0 1

You are not going to learn anything if I do your homework for you, dude :)

2006-08-24 18:27:57 · answer #5 · answered by Eve 2 · 0 1

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