2006-08-24 11:02:26 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm assuming you mean x+ 3 all over 3x^2 + 11x + 6. Since the denominator factors into (3x+2)(x+3), the x+3 in the numerator cancels out with the x+3 in the denominator and the answer is:
1/(3x+2)
2006-08-24 11:57:04 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
(x + 3)/(3x^2 + 11x + 6)
(x + 3)/((x + 3)(3x + 2))
1/(3x + 2)
2006-08-24 20:14:35 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
I think what you want is (x+3/3x^2) +11x +6 = 0...
so its,
x+3 + 33x^3 + 18x^2 = 0
or,
33x^3 + 18x^2 + x + 3 = 0... if you have to solve it, you can do that yourself. Just remember it is a 3rd order polynomial, there will be 3 roots.
2006-08-24 18:09:11 · answer #3 · answered by AresIV 4 · 0⤊ 1⤋
x+3/3x^2+11x+6
=x+3/3x^2+9x+2x+6
=x+3/3x(x+3)+2(x+3)
=x+3/(3x+2)(x+3)
=1/3x+2 is the answer
2006-08-25 09:04:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋
the answer is 3x+2. 3x^2 +11x+6 factors to (3x+2) and (x+3). the (x+3) cancels out.
At least I think that's the answer is are looking for lol.
2006-08-24 18:09:55 · answer #5 · answered by Anonymous · 1⤊ 1⤋
Assuming standard association of operators, this reduces to x^2 + 12x + 6.
2006-08-28 18:07:40 · answer #6 · answered by ecspert 2 · 0⤊ 0⤋
uum sorry
2006-08-24 18:06:10 · answer #7 · answered by aSh_=) 3 · 0⤊ 1⤋
.
2006-08-24 18:07:38 · answer #8 · answered by Redeemed 3 · 0⤊ 1⤋