Given A(1,5)and B(6,17) Find the length of AB and find the midpoint of AB.
Write 5x^-3 without negative or zero exponents
&finally
Write (7x^3y)60 without negative or zero exponents.
Thank you all in advance and thank you to all the people who have helped me before!! :)
2006-08-24 10:45:48 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
oops, the last one was actually
(7x^3y)^0
2006-08-24 10:55:23 · update #1
5^2 + 12^2 = x^2
25 + 144 = 169 = x^2
x = 13
ugh the other ones are too difficult for me, had a drink too much ;)
2006-08-24 10:52:39 · answer #1 · answered by Anonymous · 0⤊ 0⤋
length AB:
Dx = 6 - 1 = 5
Dy = 17 - 5 = 12
Length^2 = (Dx)^2 + (Dy)^2 = 25 + 144 = 169
Length = 13
midpoint: take averages of x and y
([1 + 6]/2, [5 + 17]/2) = (3.5, 11)
5x^(-3) = 5/x^3
(...)^0 = 1
as long as ... is not equal to zero
2006-08-24 18:17:10 · answer #2 · answered by dutch_prof 4 · 0⤊ 0⤋
1)length of ab=13
midpoint no idea but i would like to know plz do tell me if you come across by mailing me
2)5x^-3
5/x^3
hence
5=x^3
3)420yx^3
2006-08-24 18:09:46 · answer #3 · answered by rx.vinay.ph 2 · 0⤊ 0⤋
1) (3.5, 11)
2) 5 / (x^3)
3) You can leave that as is.
2006-08-24 17:49:17 · answer #4 · answered by mthtchr05 5 · 0⤊ 0⤋