help me solve an equation in slope-intercept form?

Question

Write the equation of a line in slope-intercept form that is parallel to the line 2x-5y= -8 and containing point (-5, 0).

Answer 1

2x - 5y = -8

solve for y.
5y = 2x + 8 - by adding 5y, then 8 to both sides
y = (2/5)x + (8/5) - by dividing through by 5

slope is 2/5, intercept is 8/5.

That's the slope-intercept form of the equation.

Now, you want a line that is parallel to that line, so a line that has slope 2/5, but intersects the point (-5,0). So:

0 = (2/5)(-5) + b
0 = -2 + b
b = 2

The line you're looking for is y = (2/5)x + 2

Answer 2

first of all you have to rewrite this equation in slope-intercept form,i.e.,y=(2/5)x+8/5.here we get the slope of this particular equation to be 2/5.Now since we want to find out the equation of a line parallel to this equation,we know that the slope would be same.Now we get y=(2/5)x+b as the equation for that line where b =y-intercept.Now since this line should contain (-5,0),
x=-5 and y=0
0=(2/5)(-5)+b
=>b=2
So,the required equation of the parallel line is y=(2/5)x+2

Answer 3

y = (2/5)x + 2

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