2006-08-24 10:22:37 · 4 answers · asked by Roberta A 1 in Science & Mathematics ➔ Mathematics
first remember the slope/intercept form of the equation for a line:
y=mx+b
the slope (m) is given in the problem so you can write:
y=-1/2x+b
we know that the line passes through (-2,4) so that means that x=-2 and y=4 is a solution for the equation of that line, so
4=-1/2(-2)+b
4=1+b
3=b
therefore the equation is
y=mx+b
y=-1/2x+3
sweet
keep at it
2006-08-24 10:27:30 · answer #1 · answered by enginerd 6 · 0⤊ 0⤋
Slope, S= (y-y')/(x-x')=-1/2
(y-4)/(x-(-2))=-1/2
2y-8=-x-2
Therefore, this is the equation of the line ====> x+2y-6=0
2006-08-24 17:30:30 · answer #2 · answered by alandicho 5 · 0⤊ 0⤋
the general fornmula to find the equation of a line is
y - y1 = m(x - x1)
where m is the slope. (x1, y1) are the given points.
in this case: m = -1/2, x1 = -2 and y1 = 4
and use this infoemation and solve it.
2006-08-24 17:29:39 · answer #3 · answered by ___ 4 · 0⤊ 0⤋
(-2,4), m = (-1/2)
4 = (-1/2)(-2) + b
4 = 1 + b
b = 3
ANS : y = (-1/2)x + 3
2006-08-24 20:20:32 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋