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Given that [H+]=[C4H7O2-] = 3.8 x 10^-3 M and [HC4H7O2] = 1 M, calculate Ka for this equilibrium.

Seriously, I need help.

2006-08-24 10:21:30 · 2 answers · asked by RED MIST! 5 in Science & Mathematics Chemistry

Forgot to add this...

H(C4H7O2) <--> C4H7O2- + H+

2006-08-24 10:31:41 · update #1

2 answers

K_a = ([H+]*[C3H7COO-])/[C2H7COOH]
K_a = (3.8*10^-3)^2/(1-3.8*10^-3) = 1.45*10^-5

2006-08-24 10:53:19 · answer #1 · answered by Anonymous · 1 0

HA<---> H +A
Ka= [H][A]/[HA]

2006-08-24 19:59:59 · answer #2 · answered by Natasha B 4 · 0 0

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