Find the missing values that solve this equation.
2x+y = 6
(2,____) (0,____) (1,____)
2006-08-24 09:08:00 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Since x is given in all instances we'll solve for y.
y=6-2x
for x=2 y=6-2*2=2
for x=0 y=6-2*0=6
for x=1 y=6-2*1=4
2006-08-24 09:12:50 · answer #1 · answered by Soscan 2 · 0⤊ 0⤋
We see that y = 6 - 2x
We have
y = 6-2(2) = 6-4= 2, giving us (2, 2);
y = 6-2(0) =6-0 =6, giving us (0, 6);
y=6-2(1) = 6-2 =4, giving us (1, 4).
2006-08-24 09:22:22 · answer #2 · answered by bassbredrin 2 · 0⤊ 0⤋
y = 5 - 4(5) = 5 - 20 = -15; so we've (5, -15) y = 5 - 4(a million) = 5 - 4 = a million; so we've (a million, a million) y = 5 - 4(-a million) = 5 + 4 = 9; so we've (-a million, 9). So the lacking values are -15, a million, and 9, respectively.
2016-09-29 22:52:20 · answer #3 · answered by ? 4 · 0⤊ 0⤋
17
2006-08-24 09:20:17 · answer #4 · answered by Paul L 2 · 0⤊ 1⤋
(_,_) represents points on a graph, x being the first numeral, and y being the second.
if x=2 then
2(2)+y=6
4+y=6
y=2
(2,2)
2(0)+y=6
y=6
(0,6)
2(1)+y=6
2+y=6
y=4
(1,4)
i hope that helps you
2006-08-24 09:13:19 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2x + y = 6
y = -2x + 6
y = -2(2) + 6
y = -4 + 6
y = 2
y = -2(0) + 6
y = 0 + 6
y = 6
y = -2(1) + 6
y = -2 + 6
y = 4
ANS : (2,2), (0,6), and (1,4)
2006-08-24 13:25:44 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
2
6
4
Seriously, all you do is plug in those values for your variable for x, and solve for y. It's not that hard.
2006-08-24 09:13:54 · answer #7 · answered by Anonymous · 0⤊ 0⤋
2,2 0,6 1,4
2006-08-24 09:12:34 · answer #8 · answered by IB 3 · 0⤊ 0⤋
2,2 0,6 1,4
2006-08-24 09:10:28 · answer #9 · answered by windfishfighter 3 · 0⤊ 0⤋
(2,2) (0,6) (1,4)
2006-08-24 09:11:33 · answer #10 · answered by glacier 4 · 0⤊ 0⤋